x^2+2x-1722=0

Solution for x^2+2x-1722=0 equation:

x^2+2x-1722=0

a = 1; b = 2; c = -1722;
Δ = b2-4ac
Δ = 22-4·1·(-1722)
Δ = 6892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6892}=\sqrt{4*1723}=\sqrt{4}*\sqrt{1723}=2\sqrt{1723}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1723}}{2*1}=\frac{-2-2\sqrt{1723}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1723}}{2*1}=\frac{-2+2\sqrt{1723}}{2}
$